if p(x) x3 +3x2 -2x+4 then find the value of p(2)+p(-2)-p(0)
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Answered by
23
p(2) = 2^3 + 3(2^2) - 2(2) + 4 = 8+12-4+4 = 20
p(-2) = -8+12+4+4 = 12
p(0) = 0+0-0+4 = 4
................................
20+12-4 = 28
p(-2) = -8+12+4+4 = 12
p(0) = 0+0-0+4 = 4
................................
20+12-4 = 28
Answered by
11
p(2)=2^3+3(2)^2-2(2)+4
=8+12-4+4
p(2) =20...........(1)
p(-2)=-8-12+4+4
=4
p(0)=4
p(2)+p(-2)-p(0)=20+4-4=20
=8+12-4+4
p(2) =20...........(1)
p(-2)=-8-12+4+4
=4
p(0)=4
p(2)+p(-2)-p(0)=20+4-4=20
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