Question

if p(x)=x³-4x²+2x-5 then find p(0)*p(2)/p(1)​

Answer 1

Answer:

The sum of the roots of P(x) is b, and the sum of the roots of Q(x)=-4, so tripling the roots of Q gives b=3*-4=-12. We triple twice to get c=(3^2)*2=18, and we triple thrice to get d=(3^3)*-5=-135. So b^3+c^3+d^3=

(-12)^3+(18)^3+(-135)^3=-2456271

Step-by-step explanation:

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Answer 2

Answer:

p(0) = x^3-4(x)^2+2x-5

p(0)= 0^3-4(0)^2+2(0)-5

p(0)= 0-0+0-5

p(0)= -5

p(2)= x^3-4(x)^2+2x-5

p(2)= 2^3-4(2)^2+2(2)-5

p(2)= 8-16+4-5

p(2)= -8+4-5

p(2)= -9

p(1) = x^3-4(x)^2+2x-5

p(1)= 1^3-4(1)^2+2(1)-5

p(1)= 1-4+2-5

p(1)= -3+2-5

p(1)= -6

Step-by-step explanation:

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