if P(x,y) is equidistant from Q(-2,5) and R(6,-1) then determine a relationship between x and y
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Answer: using distance formula
Step-by-step explanation:
PQ=PR
(-2,-5)(x, y) = (6,-1)(x, y)
Square it on both sides
(-2-x)*+ (-5-y)* = (6-x)* + (-1-y)*
4+x*+8x+25+y*+10y =36+x*-12x+1+y*+2y
=4+25-1+8x+12x+10y+2y=0
28+20x+12y=0
Divide by 2
7+5x+3y=0.
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