Question

If p(y) = 2y raise to power3- y raise to power 2– 13y – 6 then find p(1).

Answer 1

Answer:

The answer is -18.

Step-by-step explanation:

$p(y)=2{y}^3-{y}^2-13y-6$

$p(1)=2{(1)}^3-{(1)}^2-13(1)-6$

$p(1)=2-1-13-6$

$p(1)= -18$