Question

if p(y)=2y³+5y-7 than find p(-1)and p(3/2)​

Answer 1

Answer:

p(-1)= 0

p(3/2)= 29/4

Step-by-step explanation:

p(y)= 2y^3+5y-7

put d values p= -1,3/2

by putting these values we have answer

p= 0, 29/4

Answer 2

Step-by-step explanation:

p(-1)=

2×-1^3+5×-1 -7

= -2. -5 -7

=-14

=2×(3/2)^3 +5×3/2 -7

=27/4+15/2 -7

=27+30. -28////4

=29/4