Question

if p(y)=2y3-6y2-5y+10 find p(2)​

Answer 1

Answer:

$p(y) = {2y}^{3} - {6y}^{2} - 5y + 10$

$p(2) = {2(2)}^{3} - 6 {(2)}^{2} - 5(2) + 10$

$p(2) = 16 - 24 - 10 + 10$

$p(2) = - 8 - 0$

$p(2) = - 8$

Answer 2

Answer:

p(y)=2y³-6y²-5y+10

p(2)=2(2)³-6(2)²-5*2+10

⇒16-24-10+10

⇒-8

therefore, p(2)=-8

Step-by-step explanation:

hope it helps!