IF P(y)= 4+3y- y^2+5y^2 . Find p(2)
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Answered by
1
Given:p(y)=4+3y-y^2+5y^2
p(2)=4+3×2-(2)^2+5×(2)^2
=4+6-4+5×4
=10-4+20
=6+20
=26
Answer:26
Answered by
0
Answer:
15 is the answer
Step-by-step explanation:
4+3y - y² +5y²
4+3(2)-(2)²+5(2)²
4+6-4+20
30-4
26
plz follow
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