Question

If p (y)=4+3y-y^2+5y^3, find i)p(0) ii)p (2) , iii)p(-1).​

Answer 1

Answer:

I)4

II)46

III)-5

Step-by-step explanation:

P(y)=4+3y-y^2+5y^3

P(0)=4+3(0)-(0)^2+5(0)^3

=4+0-0+0

=4

P(2)=4+3(2)-(2)^2+5(2)^3

=4+6-4+40

=46

P(-1)=4+3(-1)-(-1)^2+5(-1)^3

=4-3-1-5

=-5