if p(y) 4+3y-y²+5y³ p(0)
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Answered by
6
p=0
p(0) = 5(0)^3 - (0)^2 + 3(0) +4
= 5(0) -0 + 0 +4
= 0-0+0+4
= 4
p(0) = 5(0)^3 - (0)^2 + 3(0) +4
= 5(0) -0 + 0 +4
= 0-0+0+4
= 4
Answered by
1
= 4+ 3 (0)-(0)²+5 (0)³
= 4
= 4
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