if p(y)= 4+3y-y²+5y³ p(2) and p(-1)
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p(y) = 4+3y-y²+5y³
→ p(y) = 5y³-y²+3y+4
p(2):-
p(2) = 5(2)³-(2)²+3(2)+4
= 5(8)-4+6+4
= 40+6
= 46
p(-1) = 5(-1)³-(-1)²+3(-1)+4
= 5(-1)-1-3+4
= -5-4+4
= -5
Therefore,p(2) and p(-1) are not the zeroes of the polynomial.
→ p(y) = 5y³-y²+3y+4
p(2):-
p(2) = 5(2)³-(2)²+3(2)+4
= 5(8)-4+6+4
= 40+6
= 46
p(-1) = 5(-1)³-(-1)²+3(-1)+4
= 5(-1)-1-3+4
= -5-4+4
= -5
Therefore,p(2) and p(-1) are not the zeroes of the polynomial.
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