Question

if p (y) = y square - 3√2 y+1, then find p(3√2)

Answer 1

HOLA USER ✌

HERE'S YOUR ANSWER FRIEND,

GIVEN : QUESTION ✏✏

IF p(y) = y² - 3√2y + 1

then find p(3√2)

SOLUTION ➡ p(3√2)

==> y = 3√2

Hence,

p(3√2) = (3√2)² - 3√2 X (3√2) + 1

==> 18 - 18 + 1

==> p(3√2) = 1

IS THE REQUIRED ANSWER.

HOPE IT HELPS YOU

Answer 2

Answer:

$p(y) = {y}^{2} - 3\sqrt{2} y + 1 \\ p \: (3 \sqrt{ {2} }) = 3\sqrt{ {2}^{2} } - 3 \sqrt{2} \times 3 \sqrt{2} + 1 \\ p(3 \sqrt{2} ) = 9 \times 2 - 3 \sqrt{ {2}^{2} } + 1 \\ p(3 \sqrt{2} ) = 18 - 9 \times 2 + 1 \\ p(3 \sqrt{2} ) = 18 - 18 + 1 \\ p(3 \sqrt{2} ) = 1$

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