If P(y) = y(y - 1)(y + 2), then the value of P(0) + P(1) + P(-2) is
a)0
b)1
c)-1
d)-1/2
...give me correct answer..
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Answers
Answered by
4
Answer:
0
Step-by-step explanation:
p(0) = 0(0-1)(0+2) = 0
p(1) = 1(1-1)(1+2) =0
p(-2) = -2(-2-1)(-2+2) =0
so, p(0)+p(1)+p(-2) = 0+0+0 = 0
Answered by
4
Answer:
If P(y)=y(y-1)(y+2),then the value of P(O)+ P(1) +P(-2)is =a) 0
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