Question

If p(y) = y² - 3√2 y+ 1, find p( 3√2).

p(y) = y² - 3√2 y+ 1

p(3√2) = (3√2)² - 3√2 × ______+ 1

= ________- 9× 2 + 1

= _______ - 18 +1

Hence, p(3√2) = ______.

Fill in the blanks in a proper answer​

Answer 1

Answer:

I don't know the answer

Step-by-step explanation:

• give me the point
• mark as branlist

Answer 2

Answer:

PLEASE BRAINLIEST MY ANSWER

Step-by-step explanation:

If p(y) = y² - 3√2 y+ 1, find p( 3√2).

p(y) = y² - 3√2 y+ 1

p(3√2) = (3√2)² - 3√2 × 3√2 + 1

= 9× 2 - 9× 2 + 1

= 18 - 18 +1

Hence, p(3√2) = 1 .