If p(y) =y2-3/2y+1 then find o(3/2)
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0
Answer:
Given
P(y)=y
2
−3
2y
+1
P(
3
2
)=(3
3
)
2
−3
2.(2)
2
1
+1
=(2)
3
2
−3(2
1+
3
1
)
2
1
+1
=2
3
2
−3
3
4
×
2
1
+1
=2
3
2
−3.2
3
2
+1
=−2.2
3
2
+1
=−2
3
2
+1
+1
=1−2
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