Question

If p(y)=y²-3√2y+1 then find p(3√2 ) .

Answer 1

$\textbf{Answer :}$

Given that,

p (y) = y² - 3√2y + 1

Therefore,

p (3√2)

= (3√2)² - (3√2) (3√2) + 1

= 18 - 18 + 1

= $\bold{1}$

#$\textbf{MarkAsBrainliest}$

Answer 2

Answer:

If p(y)=y²-3√2y+1

then  p(3√2 )  = 1

Step-by-step explanation:

Given polynomial is

p(y)=y²-3√2y+1

now we have to find value of p(3√2 )

this means y = 3√2

so we will Substitute the  value of y  = 3√2 in p(y)

putting the value y = 3√2 we get

p(3√2 ) = (3√2)²  - 3√2(3√2)  + 1

=> p(3√2 ) = 18  - 18  + 1

=> p(3√2 ) = 1

Hence right answer is  p(3√2 ) = 1

If p(y)=y²-3√2y+1 => p(3√2 )  = 1