two equal sides of an isoscles triangle are each 2cm more than thrice the third sides. the perimeter of triangle is 67cm, find the lenght of its sides.
Answers
Answered by
1
side1 = x
side2 = side3 = 3x+2
x + 3x+2 + 3x+2 = 67
7x + 4 = 67
7x = 63
x = 9 cm
3x+2 = 29 cm
side2 = side3 = 3x+2
x + 3x+2 + 3x+2 = 67
7x + 4 = 67
7x = 63
x = 9 cm
3x+2 = 29 cm
Similar questions