Question

If p(y) = y² - 5y + 6 find p(2), p(0)​

Answer 1

Step-by-step explanation:

Given p(y) = y^2-5y+6

1) p(2)

p(2)=2^2-5*2+6

=4-10+6

=10-10

=0

2) p(0)

p(0)=0^2-5*0+6

=0-0+6

=6

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Answer 2

Given:

1. p(y) = y² - 5y + 6

To find:

• p(2) = ?
• p(0) = ?

Method:

In the given question let us substitute the value of y as 2, 0 in the place of y

p(y) = y² - 5y + 6

p(2) = 2² - 5(2) + 6

⇒ p(2) = 4 - 10 + 6

⇒ p(2) = -6 + 6

⇒ p(2) = 0

Therefore (y - 2) is a factor of the given polynomial

p(0) = 0² - 5(0) + 6

⇒ p(0) = 0 - 0 + 6

⇒ p(0) = 6

Therefore p(0) is not a zero of the polynomial

Additional Information:

1. If any polynomial is divided by its own factor, the remainder is 0. i.e if a polynomial p(x) is divided by any binomial (x - a) the remainder obtained will be p(a)