if p(y) =y²-y+1 then what is the value of p(3)
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The given question is p(y) =y²-y+1
We have to find the value of p(3)
for p(3) sub the value 3 in the places of y in the equation p(y) =y²-y+1 , we get
on substituting the 3 in the places of y we get the final answer as 7.
Therefore, the value of p(3) = 7
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