Math, asked by hidrarana1234, 6 days ago

If P(y) = y³ - 2y² + 2y -1, then find the 1 point value of P(2)​

Answers

Answered by raniw437
0

Answer:

p(y)=y³-2y²+2y-1

p(2)=(2)³-2(2)²+2(2)-1

=8-8+4-1

=3

Step-by-step explanation:

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