If PA and PB are tangents to the circle then find angle aqr
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Draw a bi sector from o to p and u will get 20 degrees and u will get the two triangles and then use Pythagoras theorem
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/_ AQB = 70°
We can find as we know angle APB +AOB =180°
angle AOB =140°
Angle AQB =70°
Hope you will find helpful.
make it brainliest
We can find as we know angle APB +AOB =180°
angle AOB =140°
Angle AQB =70°
Hope you will find helpful.
make it brainliest
sushantzist:
can you please tell why angle aqb is half of angle aob
angle in the same segment dear 9th class theorem
Im so sorry ive been doing another problem and I wrote same method for this also
send the problem in message will discuss there
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