If PA and PB are two tangents to a circle with circle O such that APB = 80° find ABO.
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Answer:
100 degree
Step-by-step explanation:
in AOP and BOP
AP = BP
A = B = 90degree
OP = OP
by RHS congruence
AOP and BOP are congruent triangles
Apo = bpo by cpct
apo = 40 degree
by angle sum property
90 + 40 + x = 180
130 + × = 180
× = 50 degree
× = 2 AOB
AOB = 100 degree
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