if pand q are the zeroes of a quadratic polynomial ax2 +bx+c, then evaluate the following:
1) p-q
2)p÷q +q÷ p
3) 1÷ p3 +1÷ q3
4) p2 ÷q2+ q2÷p2
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Answer:
Step-by-step explanation:
ax²+bx+c
P and q are zeroes
Therefore p+q=-b/a
PQ=c/a
I) p-q
(p-q)²=p²+q²+2pq
(P-q)²=[(p+q)²-2pq]+2pq. Here (a+b)²=a²+b²+2ab so a²+b²=(a+b)²-2ab
(P-q)²=(-b/a)²
P-q=√b²/a²
p-q=b/a
ii) iii) iv) homework
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It's given in the attachment
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this is the correct above given answer
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