Math, asked by shivraj999, 4 months ago

if parallel side of trapezium are 40cm and 50cm.if its area is 135 sq.cm what is its height​

Answers

Answered by sakshi12360
0

Step-by-step explanation:

area = 1/2×h×(sum of parallel side)

135sq.cm= 1/2× h(40+50)

135sq.cm=1/2×h×90

135sq.cm= 45h

135/45= h

3cm= h

Answered by thebrainlykapil
11

Given :-

  • Shape = Trapezium
  • First Parallel Side = 40cm
  • Second Parallel Side = 50cm
  • Area of Trapezium = 134cm²

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To Find :-

  • Height of the Trapezium

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Solution :-

⇒ Area = ½ × Height × Sum of Parallel Sides

⇒ 135 = ½ × Height × ( 40 + 50 )

⇒ 135 = ½ × Height × 90

⇒ 135 × 2 = Height × 90

⇒ 270 = Height × 90

⇒ 270 ÷ 90 = Height

3cm = Height

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Verification :-

⇒ Area = ½ × Height × Sum of Parallel Sides

⇒ 135 = ½ × 3 × ( 40 + 50 )

⇒ 135 = ½ × 3 × 90

⇒ 135 = 3 × 45

⇒ 135 = 135

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Therefore, Height of the Trapezium is 3cm

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