if parallel side of trapezium are 40cm and 50cm.if its area is 135 sq.cm what is its height
Answers
Answered by
0
Step-by-step explanation:
area = 1/2×h×(sum of parallel side)
135sq.cm= 1/2× h(40+50)
135sq.cm=1/2×h×90
135sq.cm= 45h
135/45= h
3cm= h
Answered by
11
Given :-
- Shape = Trapezium
- First Parallel Side = 40cm
- Second Parallel Side = 50cm
- Area of Trapezium = 134cm²
To Find :-
- Height of the Trapezium
Solution :-
⇒ Area = ½ × Height × Sum of Parallel Sides
⇒ 135 = ½ × Height × ( 40 + 50 )
⇒ 135 = ½ × Height × 90
⇒ 135 × 2 = Height × 90
⇒ 270 = Height × 90
⇒ 270 ÷ 90 = Height
⇒ 3cm = Height
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Verification :-
⇒ Area = ½ × Height × Sum of Parallel Sides
⇒ 135 = ½ × 3 × ( 40 + 50 )
⇒ 135 = ½ × 3 × 90
⇒ 135 = 3 × 45
⇒ 135 = 135
________________
Therefore, Height of the Trapezium is 3cm
________________
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