If partical in UCM completes semicircle in pi/4 second, what is it's angular speed?
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Answer:
Explanation:
As the time required for 1/8th of the revolution is 0.05 seconds for one revolution we have 0.05 times the 8,
Therefore the time required to complete one oscillation is 0.4 seconds.
Angular velocity ω = 2π/T
Putting all the values will get,
ω = 2.5π rad/s
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