Question

The maximum tension the tail can bear is 200N. Find what can be the max force Acan apply to climb up. Mass of A is 20kg and mass of B is 5 kg.

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Answer 1

First of all, see the attached FREE BODY DIAGRAM !

• When the money B is being pulled up by monkey A (and tail doesn't tear), let's assume that they have common acceleration 'a'.

So, monkey B will also experience pseudo-force downwards, such that :

$\rm F_{tail} = m_{B}(g + a)$

$\rm \implies 200= 5(10 + a)$

$\rm \implies a = 30 \: m {s}^{ - 2}$

Now, 30 m/s² is the max value of acceleration after which the tail will break. So, the force monkey A has to pull on rope is :

$\rm F_{A}=(m_{A}+m_{B})\times(g+a)$

$\rm \implies F_{A}=(20 + 5)\times(10 + 30)$

$\rm \implies F_{A}=25\times40$

$\rm \implies F_{A}=1000 \: N$

So, force with which Monkey A has to pull is 1000 N.