Question

If PCE) = 0.25 f what is the value
of p (note)​

Answer 1

p(e)+p(not e)=1 ∵[sum of all the elementary event is 1]

∴0.25+p(not e)=1

p(not e)=1-0.25

Answer 2

Given p(e)=0.25

therefore the value of p(not e)=1-0.25

=1-0.25

=0.75

there fore the value of p(not e)=0.75