If peacock is sitting on the tree and observes it's prey on the ground It makes an angle of depression of 22 to catch the prey The speed of peacock was 10 kilometer per hour and it catches prey in 1 minute 12 seconds at what height was peacock on the tree
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∠DCA = ∠BAC = 30°
Speed of peacock is 300 m/min
= 300 m/60s
= 5 m/s
The prey is caught in 12 seconds.
Distance traveled by peacock to catch the prey = x m/12 s
x = 60 m
AC = 60 m
Height of tree = BC
In ΔABC, Sin 30° = BC/AC = BC/60 = 1/2
BC = 60/2 = 30 m
The height of tree = 30m
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