Question

if perimeter of a rhombus is 20 cm and length of one diagonal is 8 cm with is the area of the quadrilateral​

Answer 1

Answer:

Step-by-step explanation:

Answer :

Given, perimeter of a rhombus is 20 cm. and length of its one diagonal is 6 cm

Side AB =  

⟹ AB =  

⟹ AB = 5cm

The diagonal AC =6cm

Hence, AO = 3cm

∠AOB = 90 ( the two diagonals of rhombus perpendicular bisected to each other)

Hence, OB2=AB2−AO2

⟹ OB2=52−32

⟹ OB = 4cm

∴ BD = 4×2

⟹ BD = 8cm

∴ Area of the Rhombus = ×8×6

= 24 sq.cm