IF PERIMETER OF ISSOSCALE TRIANGLE IS 42 AND IT BASE IS 3/2 OF EACH OF THE SIDE .THEN FIND THE DIMENSION OF TRIANGLE
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perimeter = 42 unis
perimeter of an iso triangle= 2s + t
<s are the equal sides and t is the third side>
let s be x
42 = 2x + 3x/2
42 = 4x /2 + 3x/2
42=7x/2
transposing 2 to LHS
42*2=7x
transposing to LHS
42*2/7=x
x=12 units
So, the dimensions of the triangle are 12 units, 12 units and 18 units
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