if perimeter of square and rectangle is equal. if length and width of rectangle are 12 cm and 10 cm respectively. the area of square is what % more than that of rectangle.
Answers
Answered by
3
might be twenty percent
rishupandit789pe216y:
wrong
Answered by
6
a/c to question,
perimeter of square = perimeter of rectangle
Let side length of square is a
length of rectangle is L
and breadth of rectangle is B.
given, L = 12cm and B = 10cm
so, 4 × a = 2(L + B) [ from formula of perimeter of square and rectangle ]
4 × a = 2(12 + 10)
4a = 44 => a = 11cm
so, area of square = a² = 11² = 121cm²
and area of rectangle = L × B = 12 × 10 = 120cm²
now , area of rectangle + x % of area of rectangle = area of square
120 + x × 120/100 = 121
120 + 1.2x = 121
1.2x = 121 - 120 = 1
x = 1/1.2 = 5/6 %
hence, area of square is 5/6 % more than area of rectangle.
perimeter of square = perimeter of rectangle
Let side length of square is a
length of rectangle is L
and breadth of rectangle is B.
given, L = 12cm and B = 10cm
so, 4 × a = 2(L + B) [ from formula of perimeter of square and rectangle ]
4 × a = 2(12 + 10)
4a = 44 => a = 11cm
so, area of square = a² = 11² = 121cm²
and area of rectangle = L × B = 12 × 10 = 120cm²
now , area of rectangle + x % of area of rectangle = area of square
120 + x × 120/100 = 121
120 + 1.2x = 121
1.2x = 121 - 120 = 1
x = 1/1.2 = 5/6 %
hence, area of square is 5/6 % more than area of rectangle.
Similar questions