Question

if perpendicular from any point withinan angle on its arm are congruent prove that it lies on the bisector of that angle​

Answer 1

Step-by-step explanation:

Given that, if perpendicular from any point within, an angle on its arms is congruent, prove that it lies on the bisector of that angle

Now, Let us consider an angle ABC and let BP be one of the arm within the angle Draw perpendicular PN and PM on the arms BC and BA

such that they meet BC and BA in N and M respectively.

Now, in ΔBPM and ΔBPN

We have ∠BMP =∠BNP = 90°  [given]

BP = BP   [Common side] And MP = NP  [given]

So, by RHS congruence criterion,

we have ΔBPM ≅ ΔBPN Now,

∠MBP =∠NBP   [ ∵ Corresponding parts of congruent triangles are equal]

⇒ BP is the angular bisector of ∠ABC. ∴ Hence proved

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