if ph of H2SO4 is given 3 then find normality
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pH = -log[ H]+
So,
· [H+]=10-pH=10-3=.001M
Thus 0.001M H2SO4
Normality = Molarity * Basicity (for acids)
= 0.001 * 2 ( As H2SO4 gives 2H+ ions)
Therefore normality comes out to be 0.002N
.I hope you got it.
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