Question

If Planck's constant h is taken into a new system of units in which new unit of mass is 10g , new unit of length is 5m and new unit of time is 100s, then find the value of Planck's constant in this new system.​

Answer 1

Answer:

Explanation:

As we know that

1 joule = 1kg*(m/s)^2

If

Unit of mass =10kg

Unit of length=10m

Unit of time =1 minut =60sec

Then

1 joule=10kg*(10m/60sec)^2

1 joule=10/36kg*(m/sec)^2

Then finally

1joule=0.277kg*(m/sec)^2

Answer 2

Answer:

2.5*10^-5 Joules.

Explanation:

We know that the Planck's constant is having the unit of kg-m^2/s^2 which is having the dimensional formulae of [ML^2T^-2] this is the dimension and unit of joule which is also the unit of Planck's constant.

So, according to [ML^2T^-2] we can write that (10/1000)*(5^2)/100^2 which on solving we will get the value of Planck's constant to be 2.5*10^-5 J. So, after taking the Planck's constant to the new system the new value of the Planck's constant will be 2.5*10^-5 Joules.