If PM and RN are perpendiculars on the diagonal QS of a parallelogram PQRS. Prove that PM=RNQ.
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Step-by-step explanation:
SK = KL = QL … given … (i)
Consider ΔPKQ and ΔRLS
PQ = SR … opposite sides of parallelogram PQRS
∠PQK = ∠RSL … alternate pair of interior angles for parallel lines PQ and SR with transversal as SQ
SL = SK + KL and KQ = KL + LQ so using (i) we can say that
SL = KQ
Therefore, ΔPQK ≅ ΔRSL
⇒ ∠PKQ = ∠RLS … corresponding angles of congruent triangles
Thus PM || NR because ∠PKQ and ∠RLS are pair of alternate interior angles with transversal as KL
⇒ PM || NR … (ii)
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