If points P(x, y) , A(a, 0) and B(0, b) are collinear Divya Kota: (a) x + y = ab (b) ax + by = ab (c) bx + ay – ab = 0 (d) None
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Let the points be A(x,y), B(a,0) and C(0,b). As the points are collinear.
Area of triangle ABC is zero .
The condition for collinearity of three given points (x1,y1),(x2,y2) and (x3,y3) is
x1(y2-y3) + x2(y3-y1) + x3(y1-y2) = 0.
Thus, x(0-b) + a(b-y) + 0(y-0) = 0.
⇒ -bx + ab - ay = 0
⇒ bx + ay = ab
⇒ bx/ab + ay/ab = 1.
⇒ x/a + y/b = 1.
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