Question

if polynomial p(x)=kx³+9x²-4x-10 is divided by (x-3),it leaves a remainder -22,then find the value of k.Please answer fast.

Answer 1

Given p(x) = kx^3 + 9x^2 - 4x - 10.

Given g(x) = x - 3.

By the remainder theorem, we get

= > x - 3 = 0

= > x = 3.

plug x = 3 in p(x), we get

= > k(3)^3 + 9(3)^2 - 4(3) - 10 = -22

= > 27k + 81 - 12 - 10 = -22

= > 27k + 59 = -22

= > 27k = -81

= > k = -3.


Therefore the value of k = -3.


Hope this helps!

Answer 2

Hey!!!
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Here is your answer!!!
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x-3=0
x=3
K×3^3+9×3^2-4×3-10=-22
27k+81-12-10=-22
27k+81-22=-22
27k=-81
k=-81/27
k=-3
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I hope it helps you!!!