If polynominal p(y) is divided by (y²+2) can it have (y-1) as remainder
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Answer:
YES OFCOURSE!!!!!
Step-by-step explanation:
DIVIDEND = p(y)
DIVISOR = (y²+2)
REMAINDER = (y-1)
WE KNOW THAT DEGREE OF DIVISOR IS ALWAYS GREATER THAN OR EQUAL TO THE DEGREE OF REMAINDER.
DEGREE OF DIVISOR = DEGREE OF (y²+2) = 2
DEGREE OF REMAINDER = DEGREE OF (y-1) = 1
=> DEGREE OF DIVISOR > DEGREE OF REMAINDER
FOR EXAMPLE YOU CAN TAKE ANY POLYNOMIAL q(x) AS QUOTIENT LIKE x, x², OR ANYTHING, THEN CALCULATE p(x) = (y²+2) × q(x) + (y-1)
IT'S PRETTY MUCH EASY, I THINK YOU CAN CLARIFY.
IF YOU CAN UNDERSTAND THEN MARK MY ANSWER AS BRAINLIEST
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