If positive numbers a, b, c, d are in harmonic progression and a #b then
Answers
Answered by
0
Step-by-step explanation:
Take a=
p−3q
1
,b=
p−q
1
,c=
p+q
1
,d=
p+3q
1
Then a+d>b+c easily follows
Since (a+d)−(b+c)
=
p
2
−9q
2
2p
−
p
2
−q
2
2p
=2p[
(p
2
−9q
2
)(p
2
−q
2
)
8q
2
]
Which is positive (∵a,b,c,d>0)
Also ad−bc=
p
2
−9q
2
1
−
p
2
−q
2
1
=
(p
2
−9q
2
)(p
2
−q
2
)
8q
2
>0.
Hence, options 'A' and 'D' are correct.
Answered by
0
Step-by-step explanation:
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