Question

If potential difference across a capacitor is changed from 15v to 30v, work done is w. The work done when potential difference is charged from 30v to 60v, will be

Answer 1

work done= q*∆V = w
w= q*(30-15)
w= 15q
again
work done= q*∆V
w'= q*(60-30)
w'= 30q = 2w