Question

if potential difference between the plates of capacitor changes at the rate of dv/dt= 10^4 v/s and capacitance is 2 micrometer ,then the displacement current between the plate will be​

Answer 1

Answer:

here is your answer ...

rate of charges dv/dt = 10^4 v/s

Now capacitance =2micrometer = 2 × 10^-6

$q \: = cv \\ \frac{dq}{dt} \: = c \times \frac{dv}{dt}$

dq / dt = 2 × 10^-6 × 10^4

dq / dt = 2 × 10^-2

dq/dt = 2 × 0.001

Ic = 0.002

Ic = 20 mA

We know that displacement current

d = Ic = 20 mA

This is your answer.....

hope it helps to u dear ...