Please solve this question fast please!!!I will mark as brainliest!!Solve question 28.
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Vol.of water= 80*60*6.5
area of the cross section of the pipe= 20*20cm²= .2 *.2 m²
distance the water has to flow so that the tank would be emptied
= vol.of the water/area of the cross section
=80*60*6.5/(.2*.2) = 78000m=78 km
now,we know that v=d/t
so,t= d/v = 78/15= 5.2 hours
mark my answer as brainlist
area of the cross section of the pipe= 20*20cm²= .2 *.2 m²
distance the water has to flow so that the tank would be emptied
= vol.of the water/area of the cross section
=80*60*6.5/(.2*.2) = 78000m=78 km
now,we know that v=d/t
so,t= d/v = 78/15= 5.2 hours
mark my answer as brainlist
kuhu965:
brain list bna de answeer ko
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