Question

calculate the mole fraction of water in a mixture of 12gm water, 108gm acitic acid and 92gm ethanol

Answer 1

Hey dear friend

Mole fraction of water =(2/3)/(2/3+5/9+2)=3/16

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Answer 2

Answer:

Let the mass of solution is 100g

Then, mass of H2O=25g

mass of ethanol =25g

mass of acetic acid =50g

Number of moles of water =25g / 18gmol=1.4

Number of moles of ethanol = 25g / 46gmol =0.54

Number of moles of Acetic acid =

50g / 60gmol =0.8

Total number of moles =(1.4+0.54+0.8)=2.74

Now, mole fraction of water =

1.4/ 2.74 =0.51

mole fraction of Ethanol =

0.54 / 2.74 =0.197

mole fraction of acetic acid =

0.8 / 2.74 =0.291

Explanation:

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