Question

If potential difference between two points in a circuit is 6V, how much work is done in moving 4.8×10^20 electrons across the circuit​

Answer 1

Answer:

Step-by-step explanation:

=> Potential difference between two points in a circuit, ΔV = 6V

=> Electrons moving across the circuit​ = 4.8 * 10²⁰

[Charge of one electron =  1.602 * 10⁻¹⁹]

Thus, Charge of given electron = 1.602 * 10⁻¹⁹ * 4.8 * 10²⁰

Charge = 7.68 * 10²⁰ ⁻ ¹⁹

Charge = 7.68 * 10 = 76.9C

=> Now the formula of potential difference:

ΔV = work / charge

∴ work = potential difference ( ΔV ) * charge

= 6 * 76.8

= 460.8J.

Thus, 460.8J work is done in moving the given electrons across the circuit.​