if potential difference of electron is 1000 volt then velocity of electron???
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Answered by
1
use
1/2 mv*2 = e V
v = under the root (2eV/m)
1/2 mv*2 = e V
v = under the root (2eV/m)
Answered by
1
First convert volts to joules
E = QV
= 1.6 × 10^-19 C × 1000 V
= 1.6 × 10^-16 Joules
Kinetic energy (E) = 0.5 mv²
v = √(2E / m)
= √[(2 × 1.6 × 10^-16 Joule) / (9.1 × 10^-31 kg)]
………………[∵ Mass of electron = 9.1 × 10^-31 kg]
= 1.875 × 10^7 m/s
∴ Velocity of electron is 1.875 × 10^7 m/s
E = QV
= 1.6 × 10^-19 C × 1000 V
= 1.6 × 10^-16 Joules
Kinetic energy (E) = 0.5 mv²
v = √(2E / m)
= √[(2 × 1.6 × 10^-16 Joule) / (9.1 × 10^-31 kg)]
………………[∵ Mass of electron = 9.1 × 10^-31 kg]
= 1.875 × 10^7 m/s
∴ Velocity of electron is 1.875 × 10^7 m/s
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