Question

if PQ II RS,then find angle SOR​

Answer 1

Answer:

Since, PQ || RS, therefore angle OPS = angle OSR

thus, angle OSR = 50 degree

Now, sum of the angles of a triangle= 180 degree

Thus, angle ORS + angle OSR + angle SOR = 180 degree

= >20 degree +50 degree + angle SOR = 180 degree

=> angle SOR = 180 - 70 degree = 110 degree

thus, angle SOR is 110 degrees

Answer 2

Answer:

PQ||RS

so, angle QPS=angle PSR [alternative angle]

so, angle PSR=50°

un triangle OSR

angle ORS+angle OSR+angle ROS=180°

=> 20°+50°+angle ROS=180°

=> angle ROS=180°-(50+20)°

=180°-70°

=110°

so, angle SOR=110°