Question

If PQ is a tangent, then find the value of angle POQ + angle QPO

Answer 1

Answer:

∵ PQ is the tangent to the circle

ang PQO  =  90° (the tangent at any part of the circle is ⊥r to the radius at

                             the pt of contact)                        ..........(1)

in Δle POQ

                POQ + PQO + QPO =180°   ( ASP of a Δle)

by (1)

POQ + QPO = 90°

hope it's useful...............                

Step-by-step explanation:

Answer 2

If PQ is a tangent,then <POQ+ <QPO =90⁰

Step-by-step explanation:

we know that for a triangle sum of the interior angles is 180⁰

that is here,

<POQ+ <QPO +<OQP =180⁰

as the angle made by a tangent with line to centre of the circle is 90⁰

<OQP is 90⁰

then substitute value in a above equation we have

<POQ+ <QPO +90⁰ =180⁰

<POQ+ <QPO =180⁰-90⁰

<POQ+ <QPO =90⁰

thus the answer.

DEFINITIONS AND SOME IMPORTANT CONCEPTS TO KNOW

• Sum of the angles of the interior triangle of a triangle is 180⁰
• sum of the exterior angles of a triangle is 360⁰
• angle made by a tangent with radius (or diameter) of circle is 90⁰
• circle is set of points that are equidistant from a poin( centre of the circle).
• tangent is the line passing through only one point in a circle ,were it is perpendicular to the radius if the circle .

some more question to refer

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A regular pentagon ABCDE is fitted inside a regular hexagon APQRST such that P-B-Q, Q-C-R, R-D-S and S-E-T. Find m SED

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