Math, asked by fyawar15, 4 months ago

if pq-rs=9 and pqrs=7,find the value of p²q²+r²s²

Answers

Answered by Anonymous

3

Answer:

Given

PQ∥RS

∠QRS=∠PSR(alternateangles)=43

0

By angle sum property

27

0

+43

0

+m=180

0

m=110

0

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