Question

if ∆PQR is rt.∆ and PQ=5cm , PR=7cm and rt. angle at Q
Find the relationship between
i) sinP and cosR
ii) cosP and sinR
​

Answer 1

Answer:

Step-by-step explanation:

PR^2=PQ^2+QR^2

49-25=QR^2

QR=ROOT24

sinP=ROOT 24/7

cosR=ROOT24/7

cosP=5/7

sinR=5/7

THEREFORE,

sinP=cosR

cosP=sinR

PLEASE MARK IT BRAINLIEST IF IT HELPS