If PQR is the tangent to a circle at q whose centre is O, AB is a chord parallel to PR and angle BQR = 70 angle AQB is
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abq is 70. degreee because angle bqr=aqb
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Answer:
answer= angle aqb= 60 degree
Step-by-step explanation:
as angle bqr=60 degree, thus angle bqr= angle aqp ,bcz ab is parallel to pr and bq is transversal
now, angle bqr+ angle aqp+ angle aqb= 180 (angles on straight line)
therefore, angle aqb= 180-60-60 = 60
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