If PQR is the tangent to a circle at q whose centre is O, AB is a chord parallel to PR and angle BQR = 70 degree, then find angle AQM.
JeminPatel:
where the hell M came in to this problem, i guess you mean P
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A chord can be bisect by the center of the circle, so that the tangent will also be bisected. as one of the side is 70 degree, the rest is 20. and the other half will have the same angle
therefore AQP= 70
therefore AQP= 70
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